Question

solving a impulse, momentum problem.

If a ball falls from a roof at 20 degrees and initial speed of 10 m/s what is the velocity of the ball when it hits a table 1 meter below?

Answer 1

U know the x component of the velocity is=10*cos20

Answer 2

Y component of the velicity is=10*sin20

Answer 3

U know x component of ur initial velocity will not change. Because there is no x component of gravitational acceleration g

Answer 4

But y component of initisal velocity will b change

Answer 5

*initial

Answer 6

I think u wanna know the velocity under 1m of initial velocity. Right????

Answer 7

So y component of velocity under 1 m of initial velocity is=Vy

Answer 8

U know
Vy^2=u^2-2gh
Vy^2=(10*sin20)^2-2*9.8*(-1)
Vy=?

Answer 9

Vx=10*cos20

Answer 10

V^2=Vx^2+Vy^2

Answer 11

V=?

Answer 12

Response plz!!!!!!!!

Answer 13

Here:
Vy^2=u^2-2gh
Vy^2=(10*sin20)^2-2*9.8*(-1)
Vy=?

height is -1 but if a consider as going down to be my positive direction I can change it to 1 right?

Answer 14

so
Vx = 9.39
Vy = -7.90 (or 7.90 if we consider going down as the positive direction)
V = 12.27

Is this right?

Answer 15

Now follow up the table is rigid and weights 4kg with a length of 2 meters between the support points a and b and 1 meter from the floor. If the ball has a coefficient of restitution of 0.75. How i can obtain the impulse transferred to the beam and impulse at support points?

Answer 16

Correct!!!!!!!!!!!!!!

Answer 17

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