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Mathematics 17 Online
OpenStudy (anonymous):

A random sample of 100 undergraduate students at a university found that 78 of them had used the university librarys website to find resources for a class. What is the margin of error for the true proportion of all undergraduates who had used the librarys website to find resources for a class? a 0.04 b 0.08 c 0.1 d 0.12 @amistre64

OpenStudy (amistre64):

z(SE) sounds familiar

OpenStudy (amistre64):

how would you propose we find the standard error using the information provided?

OpenStudy (anonymous):

With a formula?

OpenStudy (amistre64):

well, the results create a formula yes :) what do you think (right or wrong) the formula for the standard error will be? give it a shot

OpenStudy (anonymous):

I used the margin of error formula and I am getting answer a 0.04.

OpenStudy (amistre64):

78(22) ----- 100^3 sqrted, yeah, me too. the thing is that is not the margin of error, it is the standard deviation of the distribution of the sample means. the margin of error requires us to use a z value multiplied to it. assuming z=1, then the margin of error is ,04

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