A warehouse ships cans of soup weighing 19 oz each in a box that weighs 6 oz. Which gives the weight of a shipped box containing n cans? A. 19(n + 6) B. 19 + (n + 6) C. 25n D. 19n + 6
pweez help
will fan and free medal :)
For every can (n) there will be 6 oz, but there will only be one box which weighs 19. So, one source of weight would be the cans, which is 6n. Another source of weight is the box which is just 19. What would that equation look like?
Oops had it backwards it should be 19n fr the cans and 6 for the box sorry
19n + (n+6)
is that right????
not quite. So, if we wanted to find the weight of 2 cans, we would take the weight (19) and multiply it by 2. If we wanted the weight of 3 cans, we would multiply 19 by 3. So, we need 19 times however many cans we have, which is our variable, n. So, 19n for the cans. Then, we will only ever have one box, which is 6 and 6 only. I f we add the weight of the cans, which we found to be 19n, and the weight of the box, which is 6, what is the equation?
19n+6
Yep! If you need more help understanding it let me know (:
*sighs* im not very smart
ok thank you!
another one???????
Don't worry about it, I've had lots of practice. Just keep working and you'll get better! @Amber123456
Sure, go ahead!
Solve using the guess-and-test strategy. Ira has 28¢ in his pocket. He has 20 coins that are either pennies or nickels. How many nickels does Ira have? A. 26 B. 22 C. 18 D. 2
??????????
@thefurball
Well, he has only 20 coins, so the answer can't be more than 20. That leaves b or c. If he had 18 nickels, how much money would he have then? Knowing that they are worth 5 cents.
ummm
I meant C or D lol
lol, sigh, idk
eed help with the answer bad I have only 60 seconds to answer this noew
D
thanks
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