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Solve the equation. Log(x+7)-logx=3 A) 3.5 B) 142.7 C) 0.0070 D) 0.0707
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There is a property with logarithms, which is\[\log(a) - \log(b) = \log(\frac{ a }{ b })\]Knowing that, we can simplify to \[\log(\frac{ x+7 }{ x }) = 3\] Do you know how to solve from there?
I do not, could you please explain further?
Ok. To solve for logs you do \[\log(x) = y \rightarrow 10^{y} = x\] so for our equation we get\[10^3 = \frac{ x + 7 }{ x }\]
okay so I now have 1000=x+7 over x would I move the x over?
Yep! So you get\[1000x = x+7\]Then you can subtract x to get\[999x = 7\]Then?
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7/999 So that would equal 0.0070 correct?
yep!
Thank you!!
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