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Mathematics 24 Online
OpenStudy (anonymous):

The speed in meters/second of a ball dropped from height h meters is given by the function v = √20h. Its kinetic energy in joules (J) is given by the function T = 2v^2. What is the ball's kinetic energy if it is dropped from a height of 3 meters? (Hint: First find speed and then find kinetic energy.)

OpenStudy (anonymous):

120 joules 60 joules 20 joules 80 joules

OpenStudy (freckles):

well you can find the speed v by using the height 3 meters first then you can find T by using that result

OpenStudy (anonymous):

sqrt(20)h?

OpenStudy (freckles):

I don't know. I can't read your v.

OpenStudy (anonymous):

sqrt(20)(3)

OpenStudy (anonymous):

They dont give you V

OpenStudy (freckles):

\[v=\sqrt{20 h} \text{ or } v=\sqrt{20} h\] yes they do I just can't tell what you mean

OpenStudy (anonymous):

so 6sqrt(5)+ 6sqrt(5)?

OpenStudy (anonymous):

nvm

OpenStudy (freckles):

what is v?

OpenStudy (freckles):

is it the first one i mentioned or the second one ?

OpenStudy (anonymous):

6qrt(5)

OpenStudy (anonymous):

v is the first one

OpenStudy (freckles):

ok \[v=\sqrt{20 h} \\ \] so you replaced h with 3 since h=3 meters \[v=\sqrt{20 \cdot 3}\] ok and we know 20*3 is 60 so \[v=\sqrt{60}\] now you can finally find T by pluggin this in to the T function you were given

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

\[2\sqrt{60}^2\]

OpenStudy (freckles):

right and that is pretty easy to calculate because the square thing will cancel the square root thing

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

thx

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