The speed in meters/second of a ball dropped from height h meters is given by the function v = √20h. Its kinetic energy in joules (J) is given by the function T = 2v^2. What is the ball's kinetic energy if it is dropped from a height of 3 meters?
(Hint: First find speed and then find kinetic energy.)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
120 joules
60 joules
20 joules
80 joules
OpenStudy (freckles):
well you can find the speed v
by using the height 3 meters
first
then you can find T by using that result
OpenStudy (anonymous):
sqrt(20)h?
OpenStudy (freckles):
I don't know.
I can't read your v.
OpenStudy (anonymous):
sqrt(20)(3)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
They dont give you V
OpenStudy (freckles):
\[v=\sqrt{20 h} \text{ or } v=\sqrt{20} h\]
yes they do
I just can't tell what you mean
OpenStudy (anonymous):
so 6sqrt(5)+ 6sqrt(5)?
OpenStudy (anonymous):
nvm
OpenStudy (freckles):
what is v?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (freckles):
is it the first one i mentioned or the second one ?
OpenStudy (anonymous):
6qrt(5)
OpenStudy (anonymous):
v is the first one
OpenStudy (freckles):
ok \[v=\sqrt{20 h} \\ \]
so you replaced h with 3 since h=3 meters
\[v=\sqrt{20 \cdot 3}\]
ok and we know 20*3 is 60
so
\[v=\sqrt{60}\]
now you can finally find T by pluggin this in to the T function you were given
OpenStudy (anonymous):
ok
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[2\sqrt{60}^2\]
OpenStudy (freckles):
right and that is pretty easy to calculate
because the square thing will cancel the square root thing