Question

Which system of equations is represented by the graph?

https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72222_53b5b0fd/0602_g3_q2.jpg

Answer 1

@freckles please help!

Answer 2

@iambatman Please help me!

Answer 3

@Data_LG2 PLease help

Answer 4

@EclipsedStar Can you please help me!

Answer 5

I see a linear function and a graph whose parent graph looks like that of f(x)=1/x

Answer 6

can you find the line?

Answer 7

that is the easier place to start

Answer 8

notice it's y-intercept and the slope

Answer 9

y=slope*x+[y-intercept]

Answer 10

@vera_ewing can you tell me the line's y-intercept?

Answer 11

are we looking at the same graph/

Answer 12

This is the answer right? y= https://lss.brainhoney.com/Resource/22181743,AD2,0,C,3,0/Assets/72222_53b5b0fd/0602_g3_q2b.gif

Answer 13

the y-axis is that vertical line

Answer 14

do you see where the line hits the y-axis?

Answer 15

0,0?

Answer 16

lol

Answer 17

@freckles

Answer 18

yes that is right

Answer 19

so the y-intercept of the line is 0

Answer 20

\[y=mx+0\]
now we need to find the slope of the line

Answer 21

you are given a point on the line (5,5) and (0,0)
use this to find the slope

Answer 22

recall slope=
\[\frac{y_2-y_1}{x_2-x_1}=\frac{5-0}{5-0}=?\]

Answer 23

1 @freckles

Answer 24

right so we got the easiest part out of the way
the line is y=1x+0
or just let's simplify it to y=x

Answer 25

now the hard part the graph whose parent graph looks like y=1/x

Answer 26

\[y=\frac{a}{x-h}+k\]

Answer 27

so first do you notice the vertical asymptote of the other function drawn there

Answer 28

No I don't understand...what would the answer be?

Answer 29

so you see no imaginary vertical line you can draw where your curve gets closer to it but never touches it?

Answer 30

remember y=1/x has vertical asymptote x=0
and horizontal asymptote y=0

it is because the curve gets closer to the a imaginary vertical line we call x=0
and an imaginary horizontal line we call y=0