How many arrangements are possible using the letters in the word FUZZY if each letter "Z" is distinctly different than the other? How many arrangements are possible if the letter "Z" is interchangeable with the other? Explain your reasoning. I just need help setting the problem up, and I should be able to do the rest. Thank you!
How many arrangements are possible using the letters in the word FUZZY if each letter "Z" is distinctly different than the other? We have 5 slots for each of the letters Slot1 = 5 choices slot2 = 4 choices (since you can't reuse a letter chosen beforehand) slot3 = 3 choices slot4 = 2 choices slot5 = 1 choice multiply out the choices to get ???
120?
correct
so that's for the first part
Okay...isn't that the same as saying "5!"?
Okay....that seemed easy lol
it is
5! = 120
How many arrangements are possible if the letter "Z" is interchangeable with the other?
We have 2 copies of Z. So the answer to this second part isn't 120 because we overcount if the Zs are indistinguishable. Since we're double counting we have to divide 120 by 2 to get 120/2 = 60
That's it? wow I cannot think today :(
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