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Mathematics 7 Online
OpenStudy (theedwardsfamily):

May I plz get some help! I'LL MEDAL + FAN :D

OpenStudy (theedwardsfamily):

OpenStudy (theedwardsfamily):

@TheSmartOne

OpenStudy (anonymous):

dirctly proportionality = u=kv

OpenStudy (theedwardsfamily):

huh?

OpenStudy (anonymous):

i think b and d

OpenStudy (jdoe0001):

hint: \(\bf \begin{array}{cccccclllll} \textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\ \textit{something}&=&{\color{brown}{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\ y&=&{\color{brown}{ n}}&\cdot&x \\\hline\\ && y={\color{brown}{ n }}x \end{array}\)

OpenStudy (jdoe0001):

something varies directly to something else = direct variation

OpenStudy (theedwardsfamily):

ithink c and b or d

OpenStudy (jdoe0001):

well... I gather we would need to differentiate it from a "inverse variation" since an inverse variation is \(\bf \begin{array}{llllll} \textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\ \textit{something}&=&\cfrac{{\color{brown}{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\ y&=&\cfrac{{\color{brown}{\textit{n}}}}{}&\cfrac{}{x} \\\hline\\ &&y=\cfrac{{\color{brown}{ n}}}{x} \end{array}\)

OpenStudy (jdoe0001):

so.. that should rule a couple more

OpenStudy (theedwardsfamily):

im so confused

OpenStudy (jdoe0001):

so... .rule out the inverse variation ones and what's left is just the direct variation ones When you have eliminated the impossible, whatever remains, however improbable, must be the truth. ~~ Sherlock Holmes, The Sign of Four Mistakes are always initial. ~

OpenStudy (theedwardsfamily):

@jabez177

OpenStudy (theedwardsfamily):

i really dont get it

OpenStudy (jdoe0001):

a direct variation means a value, changes in relation to another, by some multiplier

OpenStudy (jdoe0001):

any ideas on any of those being one?

OpenStudy (theedwardsfamily):

D and C? :/

OpenStudy (theedwardsfamily):

u there

OpenStudy (theedwardsfamily):

am i right?

OpenStudy (jdoe0001):

well D is correct C on the other hand, \(\bf 0.5\left( \cfrac{1}{u}\right)=v\implies \cfrac{0.5\cdot 1}{u}=v \\ \quad \\ \cfrac{0.5}{u}=v\impliedby \textit{inverse variation}\) now if we take a peek at B \(\bf \cfrac{v}{u}=9\implies \cfrac{v}{9}=u\implies \cfrac{1}{9}v=u\impliedby \textit{direct variation}\)

OpenStudy (theedwardsfamily):

ok. so b and d?

OpenStudy (jdoe0001):

yeap

OpenStudy (theedwardsfamily):

Yay! thank u

OpenStudy (jdoe0001):

yw

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