Question

find the solution of the square root of the quantity of x plus 3 plus 4 equals 6 and determine if it is an extraneous solution

Answer 1

\[\sqrt{x+3}+4=6\] ???

Answer 2

solution: 2, not extraneous

Answer 3

Is this the question?
$$\Large {
\sqrt{x+3}+4=6
}
$$

Answer 4

yes @perl

Answer 5

$$
\Large {
\sqrt{x+3}+4=6
\\ \therefore \\
\sqrt{x+3}=6 - 4

\\ \therefore \\
\sqrt{x+3}=2
\\ \therefore \\
(\sqrt{x+3})^2=2^2

}

$$

Answer 6

that isnt one of the answer choices

Answer 7

please finish the problem :)

Answer 8

Lisa, Perl is only trying to help you learn. Please try it out and he can help you some more.

Answer 9

Idk how to do it which is why I am here

Answer 10

did the last step make sense

Answer 11

no its where I got lost

Answer 12

ok does it make sense up to here, we can go back a step or two

Answer 13

yes it does

Answer 14

ok great :)

Answer 15

$$
\Large {
\sqrt{x+3}+4=6
\\ \therefore \\
\sqrt{x+3}=6 - 4

\\ \therefore \\
\sqrt{x+3}=2
\\ \therefore \\
(\sqrt{x+3})^2=2^2
\\ \therefore \\
x+3=2^2

}

$$

Answer 16

because \( \large (\sqrt{u})^2= u \)

Answer 17

squaring a square root cancels , for example

\( \Large (\sqrt{4}) ^2 = 4\)

Answer 18

Alright so far I understand so the answer would be 1 not extraneous

Answer 19

the last step is to test the solution in the original equation

Answer 20

and that is correct,

Answer 21

really wow thanks so much

Answer 22

$$
\Large {
\sqrt{\color{red}1+3}+4=6
}

$$

Answer 23

your welcome :)

Answer 24

What do. You. Guys. Need help qith huh