Question

You pull with a force of 300 N on a piece of luggage of mass 49 kg, but it does not move. If the coefficient of friction between the luggage and the floor is 0.95, what is the force of static friction acting on the luggage?

A. 500 N
B. 456 N
C. 300 N
D. 656 N

Answer 1

Given
m=49kg
Coefficient of friction=0.95

Answer 2

Weight of49 kg=mg=49*9.8=?

Answer 3

Static frictional force= coefficient of static friction*R=0.95*49*9.8=?

Answer 4

Because R=weight=49*9.8

Answer 5

U know R is a force acting on the object by the floor

Answer 6

Weight is a force acting on the floor by luggage

Answer 7

U know
Every action has an equal n oposit reaction

Answer 8

So weight has also an equal n oposit reaction

Answer 9

So
Weight=R

Answer 10

Weight n R oposit too

Answer 11

But we take magnitude only

Answer 12

Response plz!!!!!!!

Answer 13

Ok got it!

Answer 14

Glsd to help u!!!!!

Answer 15

*glad