Question

Anybody on that can help me with an algebra 2 question??

Answer 1

post it and we shall see

Answer 2

Okay! :)

Answer 3

seems like a big problem, is it gonna fit on here?

Answer 4

The pH of a liquid is a measure of how acidic or basic it is. The concentration of hydrogen ions in a liquid isalabeled, h+, use the formula ph=-log{h+} to find the ph level, to the nearest tenth, of a liquid with H+ about 6.2 x 10^-14

Answer 5

-14.8
14.8
13.2
-13.2

Answer 6

Its just so late and i am so confused with this math :/

Answer 7

isnt that just a calculator work?

ph = -log(h+), what is ph when h+= 6.2*10^-14

Answer 8

is your log base 10 or a natural base?

Answer 9

im not sure cause the ending all it says is 6.2 x 10^-14

Answer 10

My teacher said all it is, is you plug it in and solve but i do not even know how to plug the stuff where..

Answer 11

where it says h+, you put in the 6.2 10^(-14)

Answer 12

log in your case should pertain to base 10

what the means is that log(10) = 1

Answer 13

so ph= -log (6.2 x 10^-14)

Answer 14

ph = -log(6.2*10^(-14))

you will need to familiarize yourself with log rules if you have to do this by hand, otherwise just let the calculator do it

Answer 15

log(ab) = log(a) + log(b)

log(k^n) = n log(k)

Answer 16

I typed that in and it didnt give me a decimal, just a weird fraction

Answer 17

-log(6.2*10^(-14))

-( log(6.2) + log(10^(-14)) )

-( log(6.2) -14 log(10))

-( log(6.2) -14)

-log(6.2) +14

and a calculator gives us: log(6.2) = .7934

so what is 14 - .7924?

Answer 18

14 - .8 = 13.2 right?

Answer 19

13.2!!

Answer 20

then lets go with that one lol

Answer 21

Do you have time for a few more? Thank you very much!

Answer 22

this requires you to simply use log rules appropriately, and maybe a calculator at times.

but yeah, lets try one more.

Answer 23

thank you for showing me steps to and not just giving me it straight up,

Answer 24

Ok, so how would you expand logb 29/61

Answer 25

i know there is like 4 methods you can use to expand it..

Answer 26

use paranthesis to clarify the problem, otherwise im not sure what im looking at

Answer 27

Okie doke one sec

Answer 28

log_b \(\implies\log_b\)