What are the factors of 45855?
first try dividing by 3 because this is an odd number
or maybe try dividing by 5 because the last digit is 5
yes that makes sence I suggested 3 because the digits add up to 27
Ahh i see.. then it is also divisible by 9
I remembered this rule from way back - if you keep adding the digits until only one remains and its 3,6 or 9 then the number is divisible by 3 2 + 7 = 9 of course
I've forgotten the proof though!
than u can divide by 15
yes
thats very interesting so you're adding digits in 27 again... and keep repeating this until u get a single digit nice
yes
by 15 and than by 3 or 45 from the beginning
that works because \(10\equiv 1 \pmod{3}\) \[\begin{align}45855 &= 4*10^{4} + 5*10^3 + 8*10^2+5*10^1 + 5\\ &\equiv 4*1^{4} + 5*1^3 + 8*1^2+5*1^1 + 5\pmod{3}\\&\equiv 4+5+8+5+5\pmod{3} \end{align}\]
±1, ±3, ±5, ±9, ±15, ±45, ±1019, ±3057, ±5095, ±9171, ±15285, ±45855
that's a clever proof ' I'll have to learn more about modular arithmetic. Is there a good website teaching it?
1019 is prime
@rational do you know a good source on modular arithmetic?
http://www.math.kent.edu/~soprunova/34001s11/notes_week11.pdf it has a short tutorial talking about pure congruences w/o any other distractions @welshfella
ok thanks very much
Join our real-time social learning platform and learn together with your friends!