How do I solve x^6 when its under a square root and then under a cubed root? 3√(√x^6)
\(\sqrt[3]{\sqrt{x^6}}\) Like this?
Remember. x^6 = x * x * x * x * x * x Square root will divide the exponent by 2. 6 / 2 = ?
Yeah
I just don't understand what I'm supposed to do because of the cubed root on the outside
Would the answer just be x then?
you should get |x| i think
answer is just x if we assume x is positive
otherwise it is |x|
Thank you :)
Yep. Cube root would divide it by 3. \(x^6\) Square root: \(x^{6 \div 2} \rightarrow x^3\) Cube root: \(x^{3 \div 3} \rightarrow x\)
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