Question

200. mL of a 0.50 M NaOH solution requires 100.0 mL of a HCI solution to neutralize it. What is the concentration of the HCI solution?

I cant remember how to do this please help me understand

Answer 1

Mi*Vi=Mf*Vf (i=initial f= final) you should convers mL to L then
0.50M*0.2L=M(HCl)*0.1
M(HCL)= 1 M

Answer 2

Wow that was actually simple, thank you very much for also explaining how you got the answer. Now I get it :)

Answer 3

nothing :)

Answer 4

Just to confirm
0.50M*0.2L = M(HCl)*0.1L
0.50M(0.2L/0.1L) = M(HCl)
M(HCl) = 0.50M(2)
M(HCl) = 1M