Question

Two events A nd B in a sample space such tht p(A)=0.5,p(B)=0.25 nd p(AUB)
(a) r they mutually exclusive?why?
(b) find p(A intersection (Bcomplement))?

Answer 1

The question is missing the given value of p(AUB).

In general:
p(AUB) = p(A) + p(B) - p(A intersection B)

Mutually exclusive if: p(AUB) = p(A) + p(B).

That is, if p(A intersection B) = 0, which in English means: there is no chance that both A and B occur at the same time. This makes them mutually exclusive

Answer 2

I m also confused

Answer 3

and in general:

p(A intersection B) = p(A) * p(B)

and

Bcompliment = 1 - B

Answer 4

Plz help me i m havin exam :(

Answer 5

i can't because your question is not complete. you seem to have omitted the end (before (a) and (b))

Answer 6

can't answer (a) without knowing p(AUB)

Answer 7

P(AUB) is givem

Answer 8

to you but not to me. you forgot to write it

Answer 9

Oh sorry

Answer 10

P(AUB) is 0.70

Answer 11

So I will copy/paste part of what I wrote above.

Mutually exclusive if
p(AUB) = p(A) + p(B)

does p(AUB) = p(A) + p(B)?

Answer 12

0.7 = 0.5 + 0.25 ?

Answer 13

No becz its 0.75

Answer 14

correct. so (a) is no

Answer 15

Ok nd b??

Answer 16

p(Bcompliment) = 1 - p(B) = 1 - 0.25 = 0.75

p(A intersection Bcomp) = p(A) * p(Bcomp) = 0.5*0.75 = 0.375

Answer 17

Thank u @ euler271 :)

Answer 18

@Euler271

Answer 19

happy to help :)