Help Me To Understand How To Do This Problem Plz.
We don't know how many parrotfish or angel fish he bought. We can use the variable x to help us. He bought x number of angel fish
He bough 6 times as many parrotfish as anglefish. Since we let x equal the number of anglefish, how many parrotfish did he buy (in terms of x)?
i think he bought 70 parrotfish? Not really sure
I thought you asked for help in understanding how to solve the problem. If you want to do it your way, go ahead.
Im sorry, i thought i was doing it your way
sorry, please help me...i really dont understand this
It's ok. Let me explain myself more clearly. I am guiding you toward the correct answer and also the method of solving the problem. We need an equation that is a mathematical representation of the word problem.
We know this: number of parrotfish + number of angelfish = 420
We also know this: number of parrotfish = 6 times the number of angel fish
ok so far?
yes
We need to translate that word problem info into an algebra equation that we can solve.
In algebra, we let variables (usually letters) stand in for unknown numbers.
We have two unknown numbers, the number of parrotfish and the number of angelfish.
Let the variable x represent the number of angel fish.
can y stand for the number of parrotfish?
Since there are 6 times as many parrotfish as angel fish, the number of parrotfish is 6 times x. How do you write 6 times x in math?
6x
You can use y if you are trying to write a system of equations. Are you learning systems of equations?
Good. We have this far: x = number of angelfish 6x = number of parrtofish
Now look at what we wrote above. I'll copy it below so you don't need to look for it. number of parrotfish + number of angelfish = 420
Since the number of parrotfish is 6x, and the number of angelfish is x, we replace those words in the equation with 6x and x. 6x + x = 420 Do you understand?
yes i do, sorry i was doing something
Here the equations are color coded to make them clearer. \(\color{red}{number~of~parrotfish} + \color{green}{number~of~angelfish} = 420\) \(\color{red}{number~of~parrotfish = 6x}\) \(\color{green}{number~of~angelfish = x}\) \(\color{red}{6x} + \color{green}{x} = 420\)
okay
Now we have an equation in one variable that we can solve with algebra. \(6x + x = 420\) Add the left side: \(7x = 420\) Divide both sides by 7: \(x = 60\) We let x = number of angelfish, so the number of angelfish is 60. Since the number of parrotfish is 6x, 6 * 60 = 360. There are 360 parrotfish.
Let's check our answer: 60 + 360 = 420 The total number of fish is correct, 420. 360 = 6 * 60 The number of parrotfish is indeed 6 times the number of angelfish. Our answer is correct.
In conclusion: In problems of this type, you need to pick a variable. Then represent the situation in the word problem as an algebraic equation using the variable. Then solve the equation. Then answer the question in words. Then check the answer in the original word problem to make sure it is correct.
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