Question

The electric force between two charged objects is 0.24 newtons. If the distance between them is increased by a factor of 4, what will be the new force?
0.015 newtons
0.03 newtons
0.06 newtons
0.12 newtons
0.36 newtons

Answer 1

what does it mean by a factor of 4

Answer 2

Coulomb's Law describes the electric force between charged objects. Coulomb's Law is:
\[F=\frac{1}{4\pi \epsilon}*\frac{q_1*q_2}{r^2}=k*\frac{q_1*q_2}{r^2}\]

The relevant part iis that: \[(electric\ force) \propto \frac{1}{r^2}\]

Answer 3

and do you know the formula?
\(E_f = k\large \frac{Q_1 Q_2}{r^2} \)

Answer 4

I put Ef instead of Fe hahaha I went dyslexic

Answer 5

4^2=?

Answer 6

4^2=16

Answer 7

0.24/16=?