Question

Find the sum of first \(9\) terms of the series.

Answer 1

\(\Large \color{black }{\begin{align}
\dfrac{1^3}{1}+\dfrac{1^3+2^3}{1+3}+\dfrac{1^3+2^3+3^3}{1+3+5}+\cdots \hspace{.33em}\\~\\

\end{align}}\)

Answer 2

both numerator and denominator sums have formulas :
\[\dfrac{\left(\dfrac{n(n+1)}{2}\right)^2}{n^2}\]

simplifying gives you \(\dfrac{(n+1)^2}{4}\)

Answer 3

quick!

Answer 4

congrats you're green! i thought id get green first as you're stuck at 89 like forever haha

Answer 5

haha yes nervous nineties!