show that the area of any pythagorean triangle is integer
A triangle with integer sides is called pythagorean triangle
gotta show one one of the sides is divisible by 2
i have a proof which i don't like much... so im really looking for alternatives here
yes i think that will do !
We have to show that if a and b are odd that there is no way c can be an integer I think.
we know that one of the sides is definately and odd^2 + odd^2 = something^2
oh kai
nice ideas odd + odd = even why is this harmful
\[\Large A=\frac{ab}{2}\] if they're both odd then the area isn't an integer.
yes thats another way to state the problem, not a solution/proof.
Right, that's just my reasoning for why it's important though.
I see so it is sufficient to show that one of legs is even
No, what I'm saying is there is no integer c we can choose to make this statement true \[\Large (2n+1)^2+(2m+1)^2 = c^2\]
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