Question

helpppppp

Answer 1

Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Answer 2

If I am reading the question correctly, you are finding a confidence interval for mean body temp of men and another confidence interval for the mean body temp of women, correct?

Answer 3

i dont know i am very confused by the wording

Answer 4

For each, the confidence interval is given by \[\bar x \pm z ^{*}\frac{ \sigma }{ \sqrt{n} }\]since it was given that we have the population standard deviation, we can use the z confidence interval. In each case, the value for z* is 2.33. So, the 98% confidence interval for the population mean for the mean temperature for men is\[91.1 \pm 2.33\frac{ 0.52 }{ \sqrt{100} }\] This simplifies to the interval (90.98, 91.22). We interpret this confidence interval as follows: We are 98% confident that the mean temperature for men is between 90.98 and 91.22. The same process works for the confidence interval for women as well.

Answer 5

im still confused im sorry im kinda dumb

Answer 6

When we construct confidence intervals, we are trying to find a range of values that are very likely to contain some unknown parameter. Since we don't know what the mean body temp is for every single man and woman, we have to take a sample. It should be the case that if we take good samples, the sample mean should be close to the population mean. Does that make sense?

Answer 7

yes thank u i get that hold on let me read your other thing again

Answer 8

so the average temp is 90.98 and 91.22

Answer 9

???????

Answer 10

@Bahurverse_Luver

Answer 11

Hedoz. wut can i do?

Answer 12

help

Answer 13

lol

Answer 14

how? lol

Answer 15

i dont understand what the question is asking for

Answer 16

im nt good with math. srry i cant help you :(

Answer 17

okay so

Answer 18

imma leave you to it, k?

Answer 19

(1) you need to know what a binomial distribution looks like
(2) What standard deviation means
(3) How many standard deviations give you 98% of the population

Answer 20

(4) The Central limit theorem (Which gives you a relationship between the true standard deviation and the starndard deviation of the sample

Answer 21

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