Question

Find general formula for \(a_{n+2}=9a_{n+1}-8a_n\) where \(a_0=1, a_1=8\)
Please, help

Answer 1

I got a2=64
a3= 568
a4=4600
but still not get the formula for \(a_n\) yet,

Answer 2

@ikram002p

Answer 3

you want to use generating functions ?

Answer 4

I want recursive formula for an

Answer 5

\(a_n = 8^n\) is correct for n =0,1,2 only

Answer 6

it changes when n =3 and up

Answer 7

and I have \(a_3 = 73a_1-72a_0\)
\(a_4= 585a_1-584a_0\)

Answer 8

but need general form for an

Answer 9

brb

Answer 10

;_;
Sorry Hoa can't help now :(

Answer 11

a_0 = 1
a_1 = 8
a_2 = 9*8 - 8*1 = 64
a_3 = 9*64 - 8*8 = 512
a_4 = 9*512 - 8*64 = 4096

Answer 12

\(a_n = 8^n\) is a correct formula