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Mathematics 14 Online
OpenStudy (anonymous):

an investment of $8,200 loses value at a rate of 2% per year. what is the value of the investment after 7 years? help please

Mehek (mehek14):

first lets find 2% of 8200 can you do that?

Mehek (mehek14):

@gabbie112013 ?

OpenStudy (anonymous):

164 i think

OpenStudy (anonymous):

@Mehek14 is that right?

Mehek (mehek14):

yes

Mehek (mehek14):

now subtract 8200-164

OpenStudy (anonymous):

8036

Mehek (mehek14):

so that was for the first year

Mehek (mehek14):

now for the second find 2% of 8036

OpenStudy (anonymous):

160.72

Mehek (mehek14):

8036-160.72?

OpenStudy (anonymous):

-7875.28??

Mehek (mehek14):

7875.28 <-- 2nd yr

Mehek (mehek14):

btw this is a long process

Mehek (mehek14):

now find 2% of 7875.28

OpenStudy (anonymous):

-157.50 ?

Mehek (mehek14):

7875.28 - 157.5?

OpenStudy (anonymous):

7717.78

Mehek (mehek14):

7717.78 <--- 3rd yr

Mehek (mehek14):

2% of 7717.78?

OpenStudy (anonymous):

@Mehek14 is this exponential decay ?

OpenStudy (irishboy123):

no, its a geometric series. if an investment of X loses its value at a rate of Y% per year, then Year 0: X Year 1: X(1-Y/100) Year 2: X(1-Y/100)*(1-Y/100) Year 3: X(1-Y/100)*(1-Y/100)*(1-Y/100) Year 4: X(1-Y/100)*(1-Y/100)*(1-Y/100)*(1-Y/100) after n years, it is worth: X(1-Y/100)^n this is simple compounding.

OpenStudy (anonymous):

thanks for the help you guys :) @Mehek14 && @IrishBoy123

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