an investment of $8,200 loses value at a rate of 2% per year. what is the value of the investment after 7 years?
help please
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Mehek (mehek14):
first lets find 2% of 8200
can you do that?
Mehek (mehek14):
@gabbie112013 ?
OpenStudy (anonymous):
164
i think
OpenStudy (anonymous):
@Mehek14
is that right?
Mehek (mehek14):
yes
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Mehek (mehek14):
now subtract 8200-164
OpenStudy (anonymous):
8036
Mehek (mehek14):
so that was for the first year
Mehek (mehek14):
now for the second find 2% of 8036
OpenStudy (anonymous):
160.72
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Mehek (mehek14):
8036-160.72?
OpenStudy (anonymous):
-7875.28??
Mehek (mehek14):
7875.28 <-- 2nd yr
Mehek (mehek14):
btw this is a long process
Mehek (mehek14):
now find 2% of 7875.28
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OpenStudy (anonymous):
-157.50 ?
Mehek (mehek14):
7875.28 - 157.5?
OpenStudy (anonymous):
7717.78
Mehek (mehek14):
7717.78 <--- 3rd yr
Mehek (mehek14):
2% of 7717.78?
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OpenStudy (anonymous):
@Mehek14 is this exponential decay ?
OpenStudy (irishboy123):
no, its a geometric series.
if an investment of X loses its value at a rate of Y% per year, then
Year 0: X
Year 1: X(1-Y/100)
Year 2: X(1-Y/100)*(1-Y/100)
Year 3: X(1-Y/100)*(1-Y/100)*(1-Y/100)
Year 4: X(1-Y/100)*(1-Y/100)*(1-Y/100)*(1-Y/100)
after n years, it is worth: X(1-Y/100)^n
this is simple compounding.
OpenStudy (anonymous):
thanks for the help you guys :)
@Mehek14
&&
@IrishBoy123