How many different 3-digit even numerals can be made only using the digits 4, 1, 5, 6, 2, and 8? Assume the digits can be repeated, recall that an given digit always ends with an even number.

The only way I could think to do this was: 6(6)(4) = 144

But I feel like this is wrong? Can someone help? This is a statistics problem.

Question

How many different 3-digit even numerals can be made only using the digits 4, 1, 5,  6, 2, and 8? Assume the digits can be repeated, recall that an given digit always ends with an even number. 

The only way I could think to do this was: 6(6)(4) = 144

But I feel like this is wrong? Can someone help? This is a statistics problem.

anonymous · Answer

U have its answer?

anonymous · Answer

No, sorry, I don't have the answer to this problem.

amistre64 · Answer

its essentially right  6 and 6 and 4 choices

anonymous · Answer

How amistre?

amistre64 · Answer

no, we need an even number that is 3 digits long ....  not a number that is composed of only even digits

anonymous · Answer

Oh i got it wrong sorry ^_^

amistre64 · Answer

my only concern is that there might be duplication here

amistre64 · Answer

|dw:1428183901933:dw|

nah each path produces a unique number

6.6.4

anonymous · Answer

Thank you everyone for the help ^__^

amistre64 · Answer

good luck :)