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Chemistry 21 Online
OpenStudy (anonymous):

adding 3366.6 grams of KOH to 10L of water, find the molarity

OpenStudy (dtan5457):

molarity=number of moles/liters of solute

OpenStudy (dtan5457):

how many moles is 3366.6 grams of KOH

OpenStudy (anonymous):

okay my answer was .017 moles

OpenStudy (anonymous):

and plugging that in i got

OpenStudy (anonymous):

.0017

OpenStudy (anonymous):

but the answer is supposed to be 6M

OpenStudy (anonymous):

so im confused

OpenStudy (dtan5457):

what's the molar mass of KOH?

OpenStudy (anonymous):

56.1056

OpenStudy (dtan5457):

3366.66/56.1056=?

OpenStudy (anonymous):

i divided it the other way

OpenStudy (anonymous):

atomic mass/ grams

OpenStudy (anonymous):

is that incorrect?

OpenStudy (dtan5457):

number of moles= given mass/formula mass

OpenStudy (dtan5457):

so yes that is incorrect

OpenStudy (anonymous):

okay thanks i was unsure about that

OpenStudy (dtan5457):

so how many moles?

OpenStudy (anonymous):

60mols 6M

OpenStudy (dtan5457):

bingo

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