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The position of an object at time t is given by s(t) = -1 - 13t. Find the instantaneous velocity at t = 8 by finding the derivative.
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start by finding the derivative of s(t) ?
i dont know how to find the derivative of -1-13 because there are no exponents or anything
\[s(t) = -1-13t\] whats the derivative of \(-1\) with respect to \(t\) ?
is it -8?
nope derivative of a constant is 0
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ohh okay, so then what would the instantaneous velocity be?
there is another term in s(t) whats the derivative of \(-13t\) ?
if it helps notie that \(-13t\) is same as \(-13t^1\)
-13t^0?
yes! simplify
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-13?
thats it! \[s(t) = -1-13t\] \[s'(t) = 0 - 13 = -13\]
thank you so much!!
yw!
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