MEDAL!! What is the solution to the inequality below??
\[x^{2}\ge 36\]
\[x^{2}\ge36\] a) \[x \ge6\] b)\[-6\le x \le6\] c)\[x <-6 or x > 6\] d)\[x \le -6 or x\]
hint: \[{x^2} - 36 = \left( {x - 6} \right)\left( {x + 6} \right)\]
so we can rewrite your inequality as below: \[\left( {x - 6} \right)\left( {x + 6} \right) \geqslant 0\]
hint Square root X^2 and 36. what do you get
i know its 6 but idk the inequalities
that above inequality is equivalent to these systems: \[\begin{gathered} \left\{ \begin{gathered} x - 6 \geqslant 0 \hfill \\ x + 6 \geqslant 0 \hfill \\ \end{gathered} \right. \hfill \\ \hfill \\ \left\{ \begin{gathered} x - 6 \leqslant 0 \hfill \\ x + 6 \leqslant 0 \hfill \\ \end{gathered} \right. \hfill \\ \end{gathered} \]
what is the solution of the first system?
isn't it the answer is letter b??
I'm very sorry, I can not give you the answer directly, since the Code of Conduct
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