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Mathematics 11 Online
OpenStudy (anonymous):

Can someone please check my financial algebra work

OpenStudy (anonymous):

Missy knows that she needs $40,000 for a down payment on a house. She found an investment that earns 3.05% interest compounding monthly. She would like to purchase the home in 5 years. How much should she put in the account now to ensure she has her down payment? $8,872.33 $27,770.97 $46,580.69 I chose this response $34,349.00

OpenStudy (anonymous):

Rehan has been awarded some money in a settlement. He has the option to take a lump sum payment of $170,000 or get paid an annuity of $1,000 per month for the next 20 years. Which is the better deal for Rehan, and by how much, assuming the growth rate of the economy is 3.05% per year? Lump Sum: by $63,712.66 Lump Sum: by $7,707.19 I chose this response Annuity: by $63,712.66 Annuity: by $7,707.19

OpenStudy (anonymous):

Becky is 18 and would like to buy a house when she is 36. What is the discount factor for today’s prices if the housing values increase 6% per year? 65.0% 16.7% 12.3% 35.0% I chose this response

OpenStudy (anonymous):

acob is saving up for a down payment on a car. He plans to invest $2,000 at the end of every year for 5 years. If the interest rate on the account is 2.25% compounding annually, what is the present value of the investment? $5,666.58 $10,461.24 I chose this response $9,358.91 $37,731.88

OpenStudy (anonymous):

Sammy has an annuity that pays him $9600 at the beginning of each year. Assume the economy will grow at a rate of 3.1% annually. What is the value of the annuity if he received it now instead of over a period of 10 years? $78,044.65 $80,651.16 $81,075.98 I chose this response $83,999.29

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@abb0t

OpenStudy (campbell_st):

your 1st choice is incorrect... the investment to get a $40000 deposit is greater than the deposit. so start with A- the future value = $40000 and you need to find P the principal using the compound interest formula \[40000 = P \times (1 + \frac{3.05}{100})^{12 \times 5}\] I've assumes the interest is monthly... if its something else you'll need to change it

OpenStudy (anonymous):

ok what about number 2 @campbell_st

OpenStudy (campbell_st):

so in the 1st question is the interest per annum or per month?

OpenStudy (anonymous):

monthly right?

OpenStudy (anonymous):

so i think because it states that she found an investment that earns 3.05% interest compounding monthly.

OpenStudy (campbell_st):

ok.... well that's interesting as the answer doesn't match the choices.

OpenStudy (anonymous):

hmm

OpenStudy (campbell_st):

ok... so in question 1, the interest rate is per annum so you need to change it to monthly but you are still finding P \[40000 = A(1 + \frac{3.05 \div 12}{100})^{5 \times 60}\]

OpenStudy (anonymous):

40,000×(1+(0.0305/12))60 yeah

OpenStudy (campbell_st):

so solve for P

OpenStudy (campbell_st):

oops should be P and not A in the formula

OpenStudy (anonymous):

I got by solving 40,000×(1+(0.0305/12))60 =46580.6854454199600147

OpenStudy (anonymous):

which is the response i chose

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

just check it as I got \[P = 40000 \div (1 + 0.0305 \div 12)^{60}\]

OpenStudy (campbell_st):

which gave me the last answer

OpenStudy (campbell_st):

sorry I can't help with the others, I have to go

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