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Mathematics 18 Online
Nnesha (nnesha):

combination A combination lock has 35 numbers on it. how many different 3-digit lock combinations are possible if no digit can be repeated

Nnesha (nnesha):

the reason why i joined os months ago ;-;^

Nnesha (nnesha):

my first question was also about permutation and combination

jagr2713 (jagr2713):

Oh we did that yesterday

Nnesha (nnesha):

that question was easy

jagr2713 (jagr2713):

Oh ok b.c i remember doing combination and permutation yesterday with someone. I joined OS like 2yrs ago but they only count the days you log in so it says i only been here for 3months

Nnesha (nnesha):

there is an error

OpenStudy (amistre64):

35 numbers? not sure what 35** notation means

Nnesha (nnesha):

yea 35 numbers

TheSmartOne (thesmartone):

35 numbers how?? If it's 3 digits then it can have a max of 10 for one digit, then 9 for the second digit, and 8 for the 3rd digit..

OpenStudy (amistre64):

35 nordic runes maybe lol

Nnesha (nnesha):

it's 35 on the paper let me wear my glasses

Nnesha (nnesha):

yeah 35 numbers

Nnesha (nnesha):

answer is ) 39270

TheSmartOne (thesmartone):

Well then we would use permutations.

TheSmartOne (thesmartone):

\(\sf 35p3\)

Nnesha (nnesha):

i did and i got 6545

TheSmartOne (thesmartone):

\(\sf\Large =\frac{35!}{(35-3)!}\)

Nnesha (nnesha):

wait yeah that's right

TheSmartOne (thesmartone):

@Nnesha The question says a combination lock, so you did combinations. But we are actually supposed to use permutations to solve it.

Nnesha (nnesha):

but why permutation? if i'm nt mistaken permutation when order is important :D

TheSmartOne (thesmartone):

Because you can not repeat the number, so order is important.

TheSmartOne (thesmartone):

and thus why we use permutation. (And you are correct.)

Nnesha (nnesha):

thanks \(\large\color{green}{\rm smart!}\)

TheSmartOne (thesmartone):

Anytime \(\sf\color{green}{Nnesha!}\) :)

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