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Physics 14 Online
OpenStudy (anonymous):

A net force of 47.0 N acts on a 53.0 kg body initially at rest. Compute the work (in joules) done by the force in the first second of time. I feel like this question is really simple, but I just don't know where to start. Any help would be really appreciated. Thank you!

OpenStudy (anonymous):

Acceleration = force / mass =(47/53) [a constant] Work=force x distance distance = double integral of acceleration evaluated from t=0 to t=1, which evaluates to ½ x acceleration (still a constant) Thus, W=47 * ½(47/53) joules, or 20.8396 J

OpenStudy (anonymous):

Wow, thanks a lot! Took me a while to do the integration by myself, but I ended up getting it! Thank you very much!!

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