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Mathematics 18 Online
OpenStudy (surana):

What is the equation of the following graph?

OpenStudy (surana):

Hang on, I need to attach a file first.

OpenStudy (surana):

OpenStudy (surana):

The possible answers are: A: f(x) = x^2 + 10x -24 B: f(x) = -x^2 +10x -24 C: f(x) = x^2 -10x +24 D f(x) = -x^2 +10x +24

OpenStudy (misty1212):

HI!!

OpenStudy (surana):

Hello. Welcome, I was just asking around for help on this particular problem.

OpenStudy (misty1212):

it is a parabola that opens down, so the leading coefficient is negative skip C

OpenStudy (misty1212):

next lets find the vertex

OpenStudy (surana):

So I should skip C and A given those are both positive?

OpenStudy (misty1212):

which you see by your eyeballs is \((5,1)\)

OpenStudy (surana):

Yes, I see that.

OpenStudy (misty1212):

that means it looks like \[(x-5)^2+1\]

OpenStudy (misty1212):

multiply out, see which one you get

OpenStudy (surana):

I would get x^2 +25 +1. Which would be x^2+26.

OpenStudy (misty1212):

\[(x-5)(x-5)+1\\ x^2-20x+25+1\\ etc\]

OpenStudy (surana):

x^2 - 20x +26?

OpenStudy (misty1212):

which is none of your answers, so i would say there is a mistake in the question

OpenStudy (surana):

Yes, I believe so. So out of the answers that are possible, we've ruled out C, right?

OpenStudy (misty1212):

ooh doe i made a mistake!!

OpenStudy (misty1212):

\[-(x-5)^2+1\] there

OpenStudy (surana):

Okay, I guess we could start again then.

OpenStudy (misty1212):

\[-(x-5)(x-5)+1\\ -x^2+10x-25+1\\ -x^2-10x-24\]

OpenStudy (surana):

That would be -x^2 -25 +1, which would be -x^2 -24?

OpenStudy (misty1212):

don't forget the \(+10x\)

OpenStudy (misty1212):

\[-x^2+10x-24\] if you do the algebra

OpenStudy (surana):

-x^2 +10x - 24 is my answer? So that would mean B, then.

OpenStudy (misty1212):

i forgot the minus sign in front of the whole thing

OpenStudy (misty1212):

yeah, B

OpenStudy (surana):

Oh, very well. Thank you for helping me work through this process.

OpenStudy (misty1212):

http://www.wolframalpha.com/input/?i=-x%5E2%2B10x-24

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

OpenStudy (surana):

Thank you for helping me.

OpenStudy (owlcoffee):

Now, there is something we have to begin to analyze here. A parabola is always formed by a quadratic formula, and it opens upwards or downwards depending on the sign of the coeficent that the x squared have. if it's positive, it opens upwards and when it's negative, it opens downwards. A quadratic formula, in a factorized form, looks like: \[f(x)=(x \pm P) ( x \pm Q)\] Where "P" and "Q" are the x-intercepts, pretty much the "roots" of the equation. Wich makes it zero. Now, another important thing, the form I gave you, is a form that represents a parabola with the vertex that belongs in the y-axis. So, in order to pivot it on the x-axis, we will take the f(x+c) and it0ll move on the sides. Like this: \[f(x+c)=((x \pm c) \pm P)((x \pm c ) \pm Q)\] That would be the form of a function that has been moved in the x-axis.

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