Question

What is the A value of the following junction?

Answer 1

Hang on, I need to add the photo and answers...

Answer 2

A?

Answer 3

The possible answers are

A: 1/3
B: 1/2
C: 3
D: 2

Answer 4

ooh i bet A is supposed to be the leading coefficient right?

Answer 5

since \(f(1)=2\) i bet it is 2

Answer 6

Unlike the last one, they want the "A" Value, which I am trying to figure out.

Answer 7

also you see it is \(y=ax^2\) and since if \(x=2\) you get \(8\) it must be
\[y=2x^2\]

Answer 8

Y=2x2, so that would mean 2*2*2 = 8, so technically Y=8, but 8's not an answer.

Answer 9

So it has to be a different one, let me try again.

Answer 10

Leading coefficient? Then that would narrow it down to one of two answers.

Answer 11

A or B? 1/3 or 1/2, let me try working out what Misty said.

Answer 12

You still there Owl?

Answer 13

Still working...

Answer 14

After calculating, I think she's right, but I'd like to hear your explanation first, Owlcoffee. I thought it was the 2 since I took a look at her calculation and tried running it through, and it seemed to work.

Answer 15

any quadratic formula, has the form:
\[Ax ^{2}+Bx +C=0\]
What you can do, is take two points and evaluate them, but since the y- inteception is zero:
then it should have this form:
\[f(x) = Ax ^{2}+Bx\]
But, since it is tangent to the origin:
\[f(x)=Ax ^{2}\]
it is that way, because the parabola hasnt moved, and it is tangent to the origin.
So all we have to do is find "A", so let's take point x=2 and sww what happens:
\\[f(2)=A(2) ^{2}\]
\[4A=8\]
\[A=2\]
So therefore:
\[A=2\]

Answer 16

Thank you, so it is indeed, 2.

Answer 17

Glad to have your help, Owlcoffee.

Answer 18

And yours as well, Misty.

Answer 19

anytime, sorry I took so long, my explainations are very long haha

Answer 20

It's alright. I appreciate being able to have it explained to me.