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OpenStudy (anonymous):
AGAIN HELP ME!!
lim cos (x+1/2 pi)/ x
approaches x-> 0
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
do you get to use l'hopital's rule, or something else?
OpenStudy (misty1212):
if you cannot use it, then recognize this as the derivative of
\[\cos(x+\frac{\pi}{2})\] evaluated at \(x=0\)
OpenStudy (misty1212):
probably easier to do it the second way in any case
do you know the derivative of cosine?
OpenStudy (anonymous):
Actually Im kind of confused ! S: could show me step by step
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OpenStudy (misty1212):
lets see what you are allowed to use first
do you know derivatives?
OpenStudy (amistre64):
i was considering power series ... :)
OpenStudy (misty1212):
lol
OpenStudy (misty1212):
i have a better idea, lets use a trig identity, then it will take no steps
ok one step
OpenStudy (misty1212):
\[\cos(x+\frac{\pi}{2})=-\sin(x)\] so you have
\[-\lim_{x\to 0}\frac{\sin(x)}{x}\]
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OpenStudy (misty1212):
that limit is supposed to be well known
OpenStudy (anonymous):
Oh thanks!!!! I got it :DDDD
OpenStudy (misty1212):
did you get \(-1\) ?
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
OpenStudy (anonymous):
:D yes
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