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OpenStudy (dtan5457):
A 940 ML sample of gas is collected over water at 40.0 C. The total pressure is 85.592 KP. Calculate the volume of the dry gas at 25.0 C and 72.661 KP
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OpenStudy (dtan5457):
@aaronq
OpenStudy (dtan5457):
I got the separate dry gas pressure as 77.761 KP, and used the combined gas law (converting all celcius to kelvins )
OpenStudy (dtan5457):
then i solved for volume and I got 1001.444316...but the answer is 963.3 ml, which is still pretty far off.
OpenStudy (dtan5457):
for the volume at 25 degrees celcius and 72.661 KP, i got the dry gas from 72.661-3.169
OpenStudy (dtan5457):
maybe i wasn't suppose to do that?
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OpenStudy (dtan5457):
@Callisto
OpenStudy (aaronq):
I'm getting the same thing
\(\sf \Large \dfrac{[P^{40^o}_{T}-P^{40^o}_{water}]*V_1}{T_1}=\dfrac{[P^{25^o}_{T}-P^{25^o}_{water}]*V_2}{T_2 }\)
OpenStudy (aaronq):
V_2=1007.23 mL
OpenStudy (dtan5457):
Maybe when they say "Calculate the volume of the dry gas at 25.0 C and 72.661 KP", the dry gas pressure is really at 72.661?
OpenStudy (anonymous):
But what is the answer?
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OpenStudy (anonymous):
@dtan5457?
OpenStudy (dtan5457):
963.3 ml
OpenStudy (anonymous):
Ok.
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