Given the regular polygon, what is the measure of each numbered angle?
I think a polygon has 108 per angle.
But given this, it should be smaller.
I think it has 30 in it, so perhaps the latter two answers.
what makes you believe its 30? i come to 120 and get stuck
the measure of the internal angle of a regular polygon = \((n-2)*\dfrac{180}{n}\) where n is the number of sides. here we have 6 sides, so \(4*\dfrac{180}{6}=120\) however it looks like each angle is being bisected by those lines drawn through the center. What do you think the measure of angle 2 is now?
Wouldn't it be 60?
yeah, and then notice that there's a triangle being made with angle 2 and 1 as 2 interior angles.|dw:1428299767674:dw| find the bottom angle first
I understand how angle 2 is 60, the part I don't understand is how 120 becomes 30 degrees when you are calculating angle 1. How did you calculate that to get 30 for angle 1?
I didn't say that was 30, that says <1 as in the measurement of angle 1
|dw:1428299961094:dw|this is what we're working with
|dw:1428300029185:dw| we found that each internal angle = 120 deg
and so we're left with|dw:1428300089482:dw|
since a triangle adds up to 180 degrees you take 60 + 60 and get 120. so 180 - 120 = 60. so <1 = 60, and <2 = 60
I think so. The only problem I have with saying yes to the above work is I can't definitively say that those lines bisect the angles, it's just an assumption
thank you :)
anytime :D
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