The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 195 grams of a radioactive isotope, how much will be left after 3 half-lives?
So it cuts in half every halflife
You have 3 half lifes
( 195 / 2 ) /2 ... etc.
So we divide it by 2 three times?
hint: the decay law is: \[\large M\left( t \right) = {M_0}{e^{ - t/\tau }}\]
Not a good hint^
Yes @yesy7
Tbh that formula scares the crap out of me... I've never seen it before.
You dont need it
So I got 24.4 (i rounded)
Yup youre good.
\[\tau \] is the life time and M_0 is the mass of your sample at t=0
Oh wow that was easier than expected! Thank you both.
They dont specify lifetime
Please I don't think that 24.4 is the right result, sice we have to apply the decay law
oops..since*
Please note that, we have to apply the decay law @swagmaster47
sorry I meant that \[\tau \] is the half-life
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