Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 195 grams of a radioactive isotope, how much will be left after 3 half-lives?

OpenStudy (anonymous):

So it cuts in half every halflife

OpenStudy (anonymous):

You have 3 half lifes

OpenStudy (anonymous):

( 195 / 2 ) /2 ... etc.

OpenStudy (anonymous):

So we divide it by 2 three times?

OpenStudy (michele_laino):

hint: the decay law is: \[\large M\left( t \right) = {M_0}{e^{ - t/\tau }}\]

OpenStudy (anonymous):

Not a good hint^

OpenStudy (anonymous):

Yes @yesy7

OpenStudy (anonymous):

Tbh that formula scares the crap out of me... I've never seen it before.

OpenStudy (anonymous):

You dont need it

OpenStudy (anonymous):

So I got 24.4 (i rounded)

OpenStudy (anonymous):

Yup youre good.

OpenStudy (michele_laino):

\[\tau \] is the life time and M_0 is the mass of your sample at t=0

OpenStudy (anonymous):

Oh wow that was easier than expected! Thank you both.

OpenStudy (anonymous):

They dont specify lifetime

OpenStudy (michele_laino):

Please I don't think that 24.4 is the right result, sice we have to apply the decay law

OpenStudy (michele_laino):

oops..since*

OpenStudy (michele_laino):

Please note that, we have to apply the decay law @swagmaster47

OpenStudy (michele_laino):

sorry I meant that \[\tau \] is the half-life

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!