Mathematics
21 Online
OpenStudy (anonymous):
what does x equal, when 0=2e^(x/2)?
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OpenStudy (rizags):
so, this is what you need to solve? \[0=2e^{\frac{x}{2}}\]
OpenStudy (rizags):
is this correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
without graphing calculator :)
OpenStudy (rizags):
well, begin by dividing both sides by 2 to get \[0=e^{\frac{x}{2}}\]
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OpenStudy (freckles):
hint: can anything positive ever by 0?
OpenStudy (anonymous):
mhm I got that
OpenStudy (anonymous):
? @freckles huh?
OpenStudy (anonymous):
@Rizags what is next?
OpenStudy (anonymous):
i got to ln0 = x/2
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OpenStudy (rizags):
which is impossible
OpenStudy (rizags):
there are no solutions in the reals
OpenStudy (freckles):
e^(raise to any power) is positive
OpenStudy (anonymous):
but I don't get what ln0 means and i typed it into the calculator, which said Error
OpenStudy (freckles):
a positive number cannot be zero
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OpenStudy (anonymous):
oh what...
OpenStudy (rizags):
right, because the answer is imaginary
OpenStudy (anonymous):
but my calculus question needs the bounds to be calculated
OpenStudy (freckles):
what is the question exactly?
OpenStudy (rizags):
no solutions exist for x actually, not even imaginary ones
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OpenStudy (anonymous):
OpenStudy (anonymous):
That is the question
OpenStudy (freckles):
|dw:1428348892191:dw|
bounds are given