Question

find the distance between p1 (3,-195 degrees) and p2 (-4,-94 degrees) on the polar plane. Round your answer to the nearest thousandth.

Answer 1

here we can use the standard formula, namely:
\[ \large d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \]

Answer 2

x=1/8 @Michele_Laino

Answer 3

we have to use the subsequent formulas:
\[\left\{ \begin{gathered}
x = r\cos \theta \hfill \\
y = r\sin \theta \hfill \\
\end{gathered} \right.\]

Answer 4

for example I can write this:
\[\begin{gathered}
{x_1} = 3\cos ( - 195) = 3\cos (195) = ...? \hfill \\
{y_1} = 3\sin ( - 195) = - 3\sin (195) = ...? \hfill \\
\end{gathered} \]

Answer 5

similarly for the second point:
\[\begin{gathered}
{x_2} = 4\cos ( - 94) = 4\cos (94) = ...? \hfill \\
{y_2} = 4\sin ( - 94) = - 4\sin (94) = ...? \hfill \\
\end{gathered} \]

Answer 6

is it 4.519

Answer 7

I got 5.245