Question

Find a general formula for the nth term of the geometric series with: a6=1 and r=1/5

Answer 1

\(\Large a_{\color{brown}{ n}}=a_1r^{{\color{brown}{ n}}-1}\) does that ring a bell?

Answer 2

A(n) = (6^5)(1/5)^(n-1)

Answer 3

yes
no
no the foggiest
just posting for kicks
my cat typed it in
wrongly copied and pasted
?

Answer 4

@jdoe0001 yea thanks

Answer 5

@alyssa_nicole thats not an option :-( there is A(n) = (5^6)(1/5)^(n-1) though, is that what you meant?

Answer 6

yess.

Answer 7

ok well... we know what the 6th term is , \(\bf a_6 = 1\)
and we know what "r" is, or the common ratio, \(\bf r = \frac{1}{5}\)

so... what's the 1st term? well.. we dunno
but we know the 6th term, and the common ratio
thus