Question

@rizags @acxbox22
help me factor
3p+1=p^2+3p^3

Answer 1

first move everything to one side of the equation

Answer 2

ok so 3p+1-p^2-3p^3=0
right?

Answer 3

i can't...

Answer 4

they need to have the same exponents

Answer 5

My bad. I saw them p^3 and 3p^3
Now multiply the whole equation by -1 and arrange them from higher exponent to lower exponent.

Answer 6

why do i multiply it by a negative 1

Answer 7

It looks better as
3p^3 + p^2 - p -1 = 0
well, never mind.

Answer 8

now take -p^2 as a common factor from 3p^3 + p^2

Answer 9

how?

Answer 10

can you just write out all the steps to get the answer

Answer 11

-p^2 ( -p -1) - p - 1 = 0 now take (-p -1 )
(-p -1) ( - p^2 + 1) = 0 * -1
(p+1)(p^2 - 1) = 0 now factorize (p^2 -1 )
(p+1)(p+1)(p-1) = 0
p = 1 , -1

Answer 12

awesome thanks! can i ask some more questions on different problems?

Answer 13

Sure. But did you understand the answer ?

Answer 14

yes and no.
i dont understand how you got the first part...

Answer 15

which part exactly ?

Answer 16

what im getting is
(3p +1) (-p^2+1) making p= 1/3 and 1

Answer 17

Well, assume we have x^3 + x^2 + x + 1 = 0
we want to factorize it. So our ambition to get two similar () ex: (y+x) + (y+x) = (y+x)(1+!1).
x^3 + x^2 = -x - 1
x^3(x+1) = -x -1 now get -x -1 back to the other side x^3(x+1) + (x +1) = 0
the same as 2 +2 = 2(1+1) so (x+1)(x^3 +1 ) = 0

Answer 18

but thats not the math problem , its 3p+1=p^2+3p^3

Answer 19

I am bad at explaining. Check this : http://www.wikihow.com/Factor-a-Cubic-Polynomial

Answer 20

I was just showing you example , and you have to apply what you understand on your equation even the first solution was without the (3)

Answer 21

ok i understand your intentions but the confused me more
can u at least solve this?
m^2 +2mn +n^2-16p^2
i think its prime...?

Answer 22

n , p , m ?

Answer 23

m^2 + 2mn + n^2 = 16p^2
(m + n)(m+n) - 16p^2= 0
(4p - (m+n))(4p + (m+n))

Answer 24

(m + n)(m+n) - 16p^2 <<< 16p^2 - (m+n)^2 ( difference between two squares)

Answer 25

m^2 +2mn +n^2-16p^2
its subtracting 16...?

Answer 26

I know , factorize m^2 + 2mn + n^2 without looking at -16p^2 or get it to the other side
m^2 + 2mn + n^2 = 16p^2 same as zero the only difference is that you can't saw (m+n) = 16p^2

Answer 27

saw -> say

Answer 28

ok i really appreciate your help, but can you give me an anser so we can then talk about how we got it?

Answer 29

p = m+n/2
p = -m-n/2

Answer 30

ok, so how did that happen?

Answer 31

m^2 +2mn +n^2-16p^2 = 0
m^2 + 2nm + n^2 <-- Like any other equation but with symbols instead of numbers