Paul walks 25 feet away from his house and places a mirror on the ground. He backs 5 feet away from the mirror so that he can see the tip of the roof. Paul's eyes are 6 feet above the ground. Paul and the house are both perpendicular to the ground. The angles between the top of the house, the mirror, and the ground and between Paul's eyes, the mirror, and the ground are congruent as shown in the image:
Part 1: Prove the triangles are similar. Part 2: Determine the height of the house.
@saraked11
hey ill help yah
i can try atleast.
how do u think u start it?
do i solve what i gone know for the smaller triangle? using the Pythagorean theorem?
@ThomasMcG40
-slowly backs up because i just wanted an excuse to talk to the pretty girl-
...damnit..
I really don't know or I would help you I'm sorry!!
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would x be 30? jw?
that looks right
ok cause 5x5 =25 which is 5 for the smaller triangle and 25 for the bigger one. so then id do the same and make it 6x5= 30.. would that answer a and b?
@bibby
similarity means all the sides are in a constant proportion so i think u have to find the hypotenuse. use the pythagorean theorem sorry the site crashed
soo a^2+b^2=c^2 6^2+5^2=c^2 36+25=61 61 squared is.. 8 rounded...
did i do something wrong im confused :c @bibby
I'm sorry the site isn't cooperating with me rn, I hate openstudy so much agh don't round it yet just get it in terms of the roots \(a^2+b^2=c^2\\5^2+6^2=c^2\\c^2=25+36\\c^2=61\\c=\sqrt{61}\) do the same thing for the big one
ok. so the answer 25^2+30^2=c^2 625+900=1525
yeah and so c = sqrt 1525 the answer is to prove that the proportions of the sides are equal
rounded its 39
but when i left both answers the same without rounding it added up. the square of 61 x 5 was the number i got from square of 1525
@bibby
when I said keep it in terms of the root I meant it cause we're trying to prove that \(\dfrac{25}{5}=\dfrac {30}{6}=\dfrac{\sqrt{1525}}{\sqrt{61}}\)
wut .-.
@bibby
how do you prove 2 shapes are similar?
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