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Two vertices of a right isosceles triangle are (1,1) and (2,0). Which of the following could be the coordinates of the third vertex of this triangle?
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|dw:1428426136936:dw|
This is like Theorem of pythagoras. Finding the slant |dw:1428426307356:dw|
Finding the slant AC is the hypothenuse, by \[\frac{ 0-1 }{ 2-1 }= \frac{ -1 }{ 1 }=-1\]
Given that it is an isosceles triangle, it means that sides AB and BC have the same length or slant. Let the coordinates of B be (x,y) in an equation we can make \[\frac{ 1-y }{ 1-x }=\frac{ 0-y }{ 2-x }\]
Oops, guess I am wrong. Never mind with my work.
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