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Chemistry 7 Online
OpenStudy (anonymous):

11. What is the equilibrium constant of the following reaction when the equilibrium concentrations are as follows - [CH4] = .27M; [O2] = .86M; [CO2] = 4.9M; [H2O] = 4.2M CH4 (l)+ 2O2 (g)  CO2 (g) + 2H2O (g)

OpenStudy (aaronq):

Write the equilibrium expression, then plug in the concentrations given at equilibrium.

OpenStudy (sweetburger):

((4.9)(4.2)^2)/(.86)^2=

OpenStudy (anonymous):

thank you =)

OpenStudy (anonymous):

so 116.86?

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