Suppose 5 men and 7 women are on a crowded elevator. At the next floor, four people get off the elevator. Find the probability that three are women.

Question

anonymous · Answer

the number of ways to choose four people out of a set of 12 is $$\binom{12}{4}$$ that is your denominator

anonymous · Answer

3 are women, one is a man, 
$$\binom{7}{3}\times \binom{5}{1}$$ that is your numerator

misty1212 · Answer

HI!!

misty1212 · Answer

do you know how to compute $$\binom{7}{3}$$? sometimes this is written as $_7C_3$

anonymous · Answer

@misty1212 yes, i know it as 7C3 would it be $$7c3\div12c4$$

misty1212 · Answer

no, you need another 5 up top, because there are five men and one gets off too

misty1212 · Answer

$$\frac{_7C_3\times 5}{_{12}C_4}$$

anonymous · Answer

@misty1212 thank you so much c: that helps a lot

misty1212 · Answer

$$\color\magenta\heartsuit$$