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solving for b
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HI!!
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\[\sqrt{\frac{ b^{4} }{ 25 }} = 4 \]
would you square both sides?
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Square both sides first :)
Exactly!
does it help to know that \(\sqrt{25}=5\)?
so \[\frac{b ^{4} }{ 25 } = 16\]
and \(\sqrt{b^4}=b^2\)? i wouldn't square anything at all
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and also \(\large\sqrt{b^4}=b^{4\times \frac{1}{2}}=b^2\)
i would start with \[\frac{b^2}{5}=4\] so \[b^2=20\]
if you do it the other way you are going to have to spend a lot of time writing the answer in simplest radical form this way you get the answer in one step
so its b^2/ 5 ?
@ayyyyyyyyy25 I'll let @misty1212 take it from here. :)
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yes \[\frac{b^2}{5}=4\\ b^2=20\] now take the square root of both sides
don't forget the \(\pm\)
\[\pm 2\sqrt{5}\]
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