What is the length of the segment AB? Round to your nearest tength
first recognize that the line that passes through the vertex A is parallel to BC so we can use the two parallel lines and transverse postulates so if \[BC\parallel l ~~then~~\angle ABC =38\]
then use cosine to find AB
i'm still confused
HI!!
Hello :)
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angle A is \(90-38=52\) right?
yes because it is a right triangle
ok so \[\sin(52^\circ)=\frac{11}{h}\]
that makes \[h=\frac{11}{\sin(52^\circ)}\]
and of course a calculator
I dont know how to plug that into a calculator
as dumb as that sounds
lol i haven't used a calculator for a while now on a computer i use this http://www.wolframalpha.com/input/?i=11%2Fsin%2852%29
thank you soooooo much
hmm that's another way :)
you can also do \[h=\frac{11}{\cos38}\]
the one i started with
\[\color\magenta\heartsuit\]
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