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Hello i need help understanding an equation , i have the answer but not understanding how it was written If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add 560 mL more water to it? (340 ml)(0.5 M) = (900 ml)(Mf); Mf = 0.2 M
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M=molarity, V=volume \(\sf \huge M_iV_i=M_fV_f\) \(\sf \huge (340 mL)(0.5 M) = (340mL+560mL)M_f\) \(\sf \huge M_f=\dfrac{ (340 mL)(0.5 M)}{(340mL+560mL)}\)
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yeah lol of course
Oh! Great thanks!
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I will close this one so i can pass more medals
lol
lol ok
it looks more readable in latex :) good job
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