. What volume of add water would need to be added to the evaporated solution in problem 3 to
get a solution with a concentration of 0.25 M?

(600 ml)(0.625 M) = (Vf)(0.25 M); Vf
= 1500 ml. need to add 900 ml of water

This is the answer above just need some help getting there

Question

. What volume of add water would need to be added to the evaporated solution in problem 3 to 
get a solution with a concentration of 0.25 M? 
 
 (600 ml)(0.625 M) = (Vf)(0.25 M); Vf
 = 1500 ml. need to add 900 ml of water

This is the answer above just need some help  getting there

matlee · Answer

Hello, thanks to you i can now solve 50% of  the other things in my papare

matlee · Answer

Oh wait you need problem 3 lol

aaronq · Answer

great! that's is the actual purpose of the site, i'm glad you're learning lol

As for the answer for the question above, you already have it

it's  (600 ml)(0.625 M) = (Vf)(0.25 M)

solving (algebraically) for V_f then subtracting the initial volume (600 mL) gives you 900 mL

matlee · Answer

If I leave 750 mL of 0.50 M sodium chloride solution uncovered on a counter and 150 mL of 
the solvent evaporates, what will the new concentration of the sodium chloride solution be? 
 
 (750 ml)(0.50 M) = (600 ml)(Mf); Mf
 = 0.625 M

aaronq · Answer

$\huge \checkmark$

aaronq · Answer

it's all correct

matlee · Answer

Thanks!

aaronq · Answer

no problem, i didn't really do anything lol