Question

please helppppppp.

What is the equation of y = x3 with the given transformations?

horizontal translation right 10 units and vertical translation down 12 units
A. y = (x - 10)3 - 12
B. y = (x + 10)3 - 12
C. y = (x - 12)3 + 10
D. y = (x + 12)3 + 10

Answer 1

@bibby

Answer 2

horizontal changing x
left add and right subtract from "base" at 0
vertical adjusts the y value
positive add up
negative subtract down

Answer 3

big hint
12 down = -12 so start with A or B

Answer 4

im sorry, im really confused! any other helpful tips. i learn best if the steps are broken down.

Answer 5

if you add to the base it move the function to the left (i.e. (x+2)^2 moves 2 units left)

and moving the base to the right with subtraction

Answer 6

do i need to find the y & x intercept ? or am i totally off?

Answer 7

that's kinda unnecessary, these questions are more about function transformations. i.e. how do I push this funciton 10 units up or 3 units right or something

gimme a few mins to clean up this mess

Answer 8

okay so i made my x & y chart, and it falls to left and rises right, and i graphed it.

Answer 9

10 units right mean y=(x-10)^3
and 12 units down
y=(x-10)^3-12

Answer 10

okay, where getting somewhere. but how am i suppose to go about solving this.. im still confused.

Answer 11

moving up and down you modify the whole function f(x) (i.e. f(x)+10, f(x)-10)

moving right and left means you modify the base f(x+2) or f(x-5))

Answer 12

well it is already solved what else you need?

Answer 13

how you solved it, i understand u gave me the answer.. but how did you get it?

Answer 14

Cubic functions are in this general form