One to one inverse function help? How do I solve this?
So first it asks you to find a portion of the domain where the relationship is one-to-one. You could plot some values and graph it so you can understand this better.
Oh...the answers already include the portion. Do you know how to calculate the inverse function?
No, could you show me how? @osanseviero
Sure, it is pretty simple. Let's say you have a function y = 8x -4 What you do is you change the variables, this is a new function: x = 8y -4 And now you need to find y, so 8y = x +4 y = (x+4)/8 You need to change the variables in the function of the problem and then find the new y
Did you understand or do you prefer me to work on a new example and step by step?
@osanseviero Please
So you have a function f(x) = 3x-2 1. Replace f(x) with y. y = 3x -2 2. Change x for y and y for x x = 3y - 2 3. Solve the new equation for y 3y = x + 2 y = (x+2)/3 This is the inverse function
this looks tricky
Yep, first we need to do the inverse integral, but there are two possible answers, and there is where the domain becomes important (I'm still thinking about that part)
i think we can cheat by using the options.. there is only one interval in the options
f(x) defined in [-3, infty)
you can solve \[\\ \text{ we are given from the choices that } x \ge -3 \text{ or } x+3 \ge =0 \\ y=-(x+3)^2-4 \text{ <-- solve this for } x+3 \text{ first } \\ \text{ I will give first step } \\ \text{ add } 4 \text{ on both sides } y+4=-(x+3)^2 \]
Yes @rational, that is what I thought. The question is about the + or - at the end, but we should wait for @JoeJoldin to find the inverse first
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