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Mathematics 17 Online
OpenStudy (anonymous):

One to one inverse function help? How do I solve this?

OpenStudy (anonymous):

OpenStudy (osanseviero):

So first it asks you to find a portion of the domain where the relationship is one-to-one. You could plot some values and graph it so you can understand this better.

OpenStudy (osanseviero):

Oh...the answers already include the portion. Do you know how to calculate the inverse function?

OpenStudy (anonymous):

No, could you show me how? @osanseviero

OpenStudy (osanseviero):

Sure, it is pretty simple. Let's say you have a function y = 8x -4 What you do is you change the variables, this is a new function: x = 8y -4 And now you need to find y, so 8y = x +4 y = (x+4)/8 You need to change the variables in the function of the problem and then find the new y

OpenStudy (osanseviero):

Did you understand or do you prefer me to work on a new example and step by step?

OpenStudy (anonymous):

@osanseviero Please

OpenStudy (osanseviero):

So you have a function f(x) = 3x-2 1. Replace f(x) with y. y = 3x -2 2. Change x for y and y for x x = 3y - 2 3. Solve the new equation for y 3y = x + 2 y = (x+2)/3 This is the inverse function

OpenStudy (rational):

this looks tricky

OpenStudy (osanseviero):

Yep, first we need to do the inverse integral, but there are two possible answers, and there is where the domain becomes important (I'm still thinking about that part)

OpenStudy (rational):

i think we can cheat by using the options.. there is only one interval in the options

OpenStudy (rational):

f(x) defined in [-3, infty)

OpenStudy (freckles):

you can solve \[\\ \text{ we are given from the choices that } x \ge -3 \text{ or } x+3 \ge =0 \\ y=-(x+3)^2-4 \text{ <-- solve this for } x+3 \text{ first } \\ \text{ I will give first step } \\ \text{ add } 4 \text{ on both sides } y+4=-(x+3)^2 \]

OpenStudy (osanseviero):

Yes @rational, that is what I thought. The question is about the + or - at the end, but we should wait for @JoeJoldin to find the inverse first

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