Ask your own question, for FREE!
Physics 7 Online
OpenStudy (anonymous):

Figured it out

OpenStudy (anonymous):

@Michele_Laino say equation of motion is something like \[\dot{\theta} + \frac{ \dot l }{ l } \dot \theta + \frac{ \cos \theta }{ l } \dot{y}-\frac{ \sin \theta }{ l }\dot x=0\] the theta dot, y dot, and x dot should be all double dots, this is just a random equation of motion I found and was hoping you could help me understand if I need to find small frequency of oscillations how I would go about doing so @Michele_Laino

OpenStudy (anonymous):

I know we can expand it right, but I'm not exactly sure what that means, if you can help explain it

OpenStudy (michele_laino):

in order to get the little oscillations, we have to write the kinetic energy, and the potential energy of our system in quadratic form

OpenStudy (michele_laino):

namely we have to write: \[\large V\left( {{q_1},{q_2},...,{q_L}} \right) = \frac{1}{2}\sum\limits_{i,j} {{B_{ij}}{q_i}{q_j}} \]

OpenStudy (michele_laino):

where: \[\large {B_{ij}} = {\left. {\frac{{{\partial ^2}V}}{{\partial {q_i}\partial {q_j}}}} \right|_{{P_0}}}\]

OpenStudy (michele_laino):

and P_0, is a point of stable equilibrium, furthermore, L is the number of degree of freedom of our system

OpenStudy (michele_laino):

similarly for the kinetic energy KE

OpenStudy (anonymous):

Oh I was thinking we need this\[\cos \theta \approx 1 - \frac{ \theta^2 }{ 2 }~~~~~\sin \theta \approx \theta\]

OpenStudy (anonymous):

So wait, we just set up our equation of motion in quadratic form? OR Lagrange/ Hamiltonian

OpenStudy (michele_laino):

it should be better if we solve an exercise

OpenStudy (anonymous):

Yes, um let me see if I can find a problem

OpenStudy (michele_laino):

I have found one exercise of mine

OpenStudy (anonymous):

Ok that works

OpenStudy (michele_laino):

here is the text: A system is composed by three identical pendulums, with the same mass and with the same length. Those masses are connecte each other by two springs, whose constant is K. At the equilibrium all three pendulums are vertical and the springs are in a rest position

OpenStudy (michele_laino):

here is the drawing: |dw:1428484298008:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!